Economics 320: Industrial Organization and Pricing
Problem Set #5 Solutions
Two firms supply an industry with a demand curve of Q(P)=200-5P
and each firm has an constant marginal (and average) cost of $1. Please
fill in the following chart and attach a sheet of paper showing all formulas
and work.
| Model | Firm Output | Price | Firm Profit | Consumer Surplus |
| Collusion | 48.75 | $20.50 | $950.62 | 950.62 |
| Cournot | 65 | $14 | $845 | 1690 |
| Bertrand | 97.5 | $1 | $0 | 3802.5 |
Graduate Students (and Extra Credit for Undergraduates): Derive the
Stackelberg result (output) for the example used in the text (attached
is the mathematical derivation from another book):
Market Demand: Q=1000 - 1000P
MC=$0.28
Caution: I'm not sure that the answer listed in Table 7.1 is correct.
Collusion
The collusion solution is the found by finding the monopoly solution
and dividing output among the firms (in this case 2). The monopoly solution
is found by MR=MC.
P=40-1/5Q
TR = PQ = (40-1/5Q)Q
MR = 40-2/5Q = MC = 1
39=2/5Q
Q=97.5
q=48.75
P=40-1/5Q=40-1/5(97.5)=20.5
Profit of the firm = (P-AC)q = 19.5*48.75 = 950.625
Consumer Surplus = ½ hb = ½ (40-20.5) 97.5 = 950.625 (40
comes from finding P when Q=0)
Cournot
Profit1 = TR=TC = Pq1-1q1 = (40-1/5Q)q1-q1 = (40-1/5(q1+q2))q1-q1
dprofit1/dq1 = 40-2/5q1-1/5q2-1 = 0
39=2/5q1+1/5q2
q1=95-1/2q2 (reaction curve)
by symmetry q2=95-1/2q1
solving both reaction curves simultaneously
-39=3/5q1
q1=65=q2
Q=130
Find P by solving P=40-1/5(Q)=40-1/5(130)=14
profit for the firm = (P-AC) q = 13*65=845
Consumer Surplus = ½ (40-14) 130 = 1690
Bertrand Model
Bertrand is similar to the competitive outcome where P=MC, P=MC=1, Q=200-5P
= 195
q = Q/2 = 97.5
Profit for the firm = (P-AC) q = (0) *97.5 = 0
Consumer Surplus = ½ (40-1) (195) = 3802.5
Stackelberg n-firms
P=1-.001Q=1-.001(q1+(n-1)qf)
profit f = P(Q)qf-.28qf
dprofit f/dqf = [d(P(Q))/dqf]qf + P(Q)dqf/dqf-.28=.001qf+(1-.001(q1+(n-1)qf))-.28=
.72-.001q1-.001qf(n-1+1)=0
qf=(.72-.001q1)/.001n
Firm L (1) recognizes all n followers will behave acording to this reaction
function:
(n-1)dqf/dq1=(n-1)(-1/n)=-(n-1)/n
Firm L's profit maximization is
profit 1 = p(Q)q1-.28q1
dprofit 1/dq1 = p(Q)+ql*dP(Q)/dq1-.28
dP(Q)/dq1=-.001 * dQ/dq1=-.001 *(dq1/dq1+dqf/dq1)=-.001* (1-(n-1)/n)
dprofit 1/dq1=(1-.001(q1+(n-1)qf))-.001(1-(n-1)/n)q1-.28=0
.72-.001q1-.001(n-1)(.72-.001q1)/.001n-.001(1-(n-1)/n)q1=0
.72(1-(n-1)/n)-.001q1(1-(n-1)/n+1/n)=0
.72/n-.001q1(2/n)=0
q1=360
qf=(.72-.001(360))/.001n=360/n